What is factor a^2-b^2-10a+25 ?

The solution to factor a^2-b^2-10a+25 is (a-5+b)(a-5-b)

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factor a^2-b^2-10a+25

factor

a^{2} - b^{2} - 10 a + 25

(a - 5 + b) (a - 5 - b)

Solution steps

a^{2} - b^{2} - 10 a + 25

Factor

a^{2} - 10 a + 25 : (a - 5)^{2}

= (a - 5)^{2} - b^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(a - 5)^{2} - b^{2} = ((a - 5) + b) ((a - 5) - b)

= ((a - 5) + b) ((a - 5) - b)

Apply rule:

(a) = a

(a - 5) = a - 5

= (a - 5 + b) (a - 5 - b)

(0.5 x + 0.4 y)^{2} - (0.5 x - 0.4 y)^{2}

(\frac{2}{3 x + 1})^{3}

\frac{( 2 x - 6 )}{( x ^{2} - 2 x - 3 )}

\frac{( x ^{2} - 3 x )}{( x ^{2} - 9 )}

(x + 2) (x + 3)^{3}

What is factor a^2-b^2-10a+25 ?
The solution to factor a^2-b^2-10a+25 is (a-5+b)(a-5-b)