What is factor 2x^4+x^3-14x^2-19x-6 ?

The solution to factor 2x^4+x^3-14x^2-19x-6 is (x+1)(2x+1)(x+2)(x-3)

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factor 2x^4+x^3-14x^2-19x-6

factor

2 x^{4} + x^{3} - 14 x^{2} - 19 x - 6

(x + 1) (2 x + 1) (x + 2) (x - 3)

Solution steps

2 x^{4} + x^{3} - 14 x^{2} - 19 x - 6

Use the rational root theorem

= (x + 1) \frac{2 x ^{4} + x ^{3} - 14 x ^{2} - 19 x - 6}{x + 1}

\frac{2 x ^{4} + x ^{3} - 14 x ^{2} - 19 x - 6}{x + 1} = 2 x^{3} - x^{2} - 13 x - 6

= (x + 1) (2 x^{3} - x^{2} - 13 x - 6)

Factor

2 x^{3} - x^{2} - 13 x - 6 : (2 x + 1) (x + 2) (x - 3)

= (x + 1) (2 x + 1) (x + 2) (x - 3)

\frac{1}{2 x y ^{2} ( \frac{2}{3} x y - 3 )}

\frac{1}{2} x + \frac{1}{x}

\frac{t ^{n - 1}}{( 1 - e ^{- t} )}

2 x - 1 + 6 x y - 3 y

a \cdot 2.64 d^{3} + 216 a^{3}

What is factor 2x^4+x^3-14x^2-19x-6 ?
The solution to factor 2x^4+x^3-14x^2-19x-6 is (x+1)(2x+1)(x+2)(x-3)