What is (sin^2(x))/(cos(x)-1+cos(x)) ?

The solution to (sin^2(x))/(cos(x)-1+cos(x)) is (sin^2(x))/(2cos(x)-1)

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simplify (sin^2(x))/(cos(x)-1+cos(x))

simplify

\frac{sin ^{2} ( x )}{cos ( x ) - 1 + cos ( x )}

\frac{sin ^{2} ( x )}{2 cos ( x ) - 1}

Solution steps

\frac{sin ^{2} ( x )}{cos ( x ) - 1 + cos ( x )}

Group like terms

= \frac{sin ^{2} ( x )}{cos ( x ) + cos ( x ) - 1}

Add similar elements:

cos (x) + cos (x) = 2 cos (x)

= \frac{sin ^{2} ( x )}{2 cos ( x ) - 1}

25 x^{4} - y^{6}

x^{6} - 81 x^{4}

2 cos^{2} (x) - cos (x)

\frac{( n + 1 ) ! ( n + 2 )}{( n - 1 ) !}

p^{\frac{2}{5}} \cdot p^{- 2}

What is (sin^2(x))/(cos(x)-1+cos(x)) ?
The solution to (sin^2(x))/(cos(x)-1+cos(x)) is (sin^2(x))/(2cos(x)-1)