What is expand 2x+i(x^2-1) ?

The solution to expand 2x+i(x^2-1) is 2x+(x^2-1)i

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expand 2x+i(x^2-1)

expand

2 x + i (x^{2} - 1)

2 x + (x^{2} - 1) i

Solution steps

2 x + i (x^{2} - 1)

Apply the distributive law:

a (b - c) = ab - a c

i (x^{2} - 1) = i x^{2} - i 1

= 2 x + i x^{2} - i 1

Simplify

i x^{2} - i 1 : x^{2} i - i

= 2 x + x^{2} i - i

Rewrite in standard complex form:

2 x + (x^{2} - 1) i

= 2 x + (x^{2} - 1) i

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