What is factor 1+z^6 ?

The solution to factor 1+z^6 is (z^2+1)(z^4-z^2+1)

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factor 1+z^6

factor

1 + z^{6}

(z^{2} + 1) (z^{4} - z^{2} + 1)

Solution steps

1 + z^{6}

Write in the standard form

= z^{6} + 1

Apply exponent rules

= (z^{2})^{3} + 1^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(z^{2})^{3} + 1^{3} = (z^{2} + 1) (z^{4} - z^{2} + 1)

= (z^{2} + 1) (z^{4} - z^{2} + 1)

(\frac{8 a ^{3}}{27 \cdot x ^{- 3}})^{\frac{- 1}{3}}

(1.5 y + 0.5)^{2}

p \cdot q^{2} - p^{2} \cdot q^{3} - 2 p^{3} \cdot q^{5} \cdot r + p^{2} \cdot q^{3} \cdot r^{2}

6 x^{3} + 3 x^{2} - 5 x + 1

\frac{ln ( 1 )}{x ^{2}}