What is factor 2a*b^2+b^3-5b^2+6a+3b-15 ?

The solution to factor 2a*b^2+b^3-5b^2+6a+3b-15 is (2a+b-5)(b^2+3)

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factor 2a*b^2+b^3-5b^2+6a+3b-15

factor

2 a \cdot b^{2} + b^{3} - 5 b^{2} + 6 a + 3 b - 15

(2 a + b - 5) (b^{2} + 3)

Solution steps

2 a b^{2} + b^{3} - 5 b^{2} + 6 a + 3 b - 15

= (2 a b^{2} + b^{3} - 5 b^{2}) + (6 a + 3 b - 15)

Factor out

b^{2}

from

2 a b^{2} + b^{3} - 5 b^{2} : b^{2} (2 a + b - 5)

Factor out

3

from

6 a + 3 b - 15 : 3 (2 a + b - 5)

= b^{2} (2 a + b - 5) + 3 (2 a + b - 5)

Factor out common term

2 a + b - 5

= (2 a + b - 5) (b^{2} + 3)

44 z + 20 z^{2} - 15

(\frac{b ^{2}}{c ^{3}})^{9}

4 sin^{3} (x) - 3 sin (x) + sin^{3} (x)

(4 m^{2} \cdot n^{3})^{2}

l^{- 1} \cdot ⎩ ⎨ ⎧ \frac{s}{( ( s - 1 ) ^{4} )} ⎭ ⎬ ⎫

What is factor 2a*b^2+b^3-5b^2+6a+3b-15 ?
The solution to factor 2a*b^2+b^3-5b^2+6a+3b-15 is (2a+b-5)(b^2+3)