What are the solutions to the equation 37x^2=495^2 ?

The solutions to the equation 37x^2=495^2 are x=(495)/(sqrt(37)),x=-(495)/(sqrt(37))

Find the zeros of 37x^2=495^2

The zeros of 37x^2=495^2 are x=(495)/(sqrt(37)),x=-(495)/(sqrt(37))

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37 x^{2} = 49 5^{2}

x = \frac{495}{37}, x = - \frac{495}{37}

Decimal Notation

x = 81.37749 \dots, x = - 81.37749 \dots

Solution steps

37 x^{2} = 49 5^{2}

49 5^{2} = 245025

37 x^{2} = 245025

Divide both sides by

37

x^{2} = \frac{245025}{37}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{245025}{37}, x = - \frac{245025}{37}

\frac{245025}{37} = \frac{495}{37}

- \frac{245025}{37} = - \frac{495}{37}

x = \frac{495}{37}, x = - \frac{495}{37}

∣ x + 4 ∣ > 9

1 - x > 0

- 100 x (- 25 x^{2} + 9) > 0

- x^{2} - 5 x - 6 = 0

- \frac{5}{3} + \frac{13}{9} (- 1.1 + 1)

What are the solutions to the equation 37x^2=495^2 ?
The solutions to the equation 37x^2=495^2 are x=(495)/(sqrt(37)),x=-(495)/(sqrt(37))
Find the zeros of 37x^2=495^2
The zeros of 37x^2=495^2 are x=(495)/(sqrt(37)),x=-(495)/(sqrt(37))