What is [\sqrt[4]{1x}^{-1}2]^{-2}3 ?

The solution to [\sqrt[4]{1x}^{-1}2]^{-2}3 is (3sqrt(x))/4

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simplify [\sqrt[4]{1x}^{-1}2]^{-2}3

simplify

\frac{3 x}{4}

Solution steps

Apply rule:

1 \cdot a = a

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

Simplify

= 3 \cdot \frac{1}{\frac{4}{x}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= 3 \cdot \frac{x}{4}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 x}{4}

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What is [\sqrt[4]{1x}^{-1}2]^{-2}3 ?
The solution to [\sqrt[4]{1x}^{-1}2]^{-2}3 is (3sqrt(x))/4