What is factor 4m^4+35m^2n^2+121n^4 ?

The solution to factor 4m^4+35m^2n^2+121n^4 is (2m^2+11n^2+3mn)(2m^2+11n^2-3mn)

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factor 4m^4+35m^2n^2+121n^4

factor

4 m^{4} + 35 m^{2} n^{2} + 121 n^{4}

(2 m^{2} + 11 n^{2} + 3 mn) (2 m^{2} + 11 n^{2} - 3 mn)

Solution steps

4 m^{4} + 35 m^{2} n^{2} + 121 n^{4}

Add and subtract

9 m^{2} n^{2}

= 4 m^{4} + 44 m^{2} n^{2} + 121 n^{4} - 9 m^{2} n^{2}

Factor

4 m^{4} + 44 m^{2} n^{2} + 121 n^{4} : (2 m^{2} + 11 n^{2})^{2}

= (2 m^{2} + 11 n^{2})^{2} - 9 m^{2} n^{2}

Apply exponent rules

= (2 m^{2} + 11 n^{2})^{2} - (3 mn)^{2}

Factor

(2 m^{2} + 11 n^{2})^{2} - (3 mn)^{2} : (2 m^{2} + 11 n^{2} + 3 mn) (2 m^{2} + 11 n^{2} - 3 mn)

= (2 m^{2} + 11 n^{2} + 3 mn) (2 m^{2} + 11 n^{2} - 3 mn)

(4 x^{2} - 1) (4 x^{2} + 1)

\frac{7 p ^{6}}{7 c ^{6}}

\frac{2 x ^{4} - 3 x ^{4} + 3 x ^{2}}{x ^{6}}

\frac{( a ^{3} - 2 a ^{2} \cdot b )}{( 2 a ^{3} \cdot b ^{2} - a ^{4} \cdot b )}

\frac{1}{2} + \frac{1}{2} + 4 + 6 + \frac{1}{2} + 4 + 6 + 8 + \frac{1}{2} + 4 + 6 + 8 + 2 n

What is factor 4m^4+35m^2n^2+121n^4 ?
The solution to factor 4m^4+35m^2n^2+121n^4 is (2m^2+11n^2+3mn)(2m^2+11n^2-3mn)