What are the solutions to the equation p^2-64=0 ?

The solutions to the equation p^2-64=0 are p=8,p=-8

Find the zeros of p^2-64=0

The zeros of p^2-64=0 are p=8,p=-8

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p^{2} - 64 = 0

p = 8, p = - 8

Solution steps

p^{2} - 64 = 0

Move

64

to the right side

p^{2} = 64

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

p = 64, p = - 64

64 = 8

- 64 = - 8

p = 8, p = - 8

\frac{1}{2} (8 - x) > 6

16 x^{4} - 8 x^{2} y^{2} + y^{4}

(\frac{4}{5})^{2} + y^{2} = 1

- 2 x^{2} > x - 1

3 w^{2} - 5 w - 50 = 0

What are the solutions to the equation p^2-64=0 ?
The solutions to the equation p^2-64=0 are p=8,p=-8
Find the zeros of p^2-64=0
The zeros of p^2-64=0 are p=8,p=-8