What is ((1/9 x)^2-2)/(3x-1) ?

The solution to ((1/9 x)^2-2)/(3x-1) is (-162+x^2)/(81(3x-1))

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simplify ((1/9 x)^2-2)/(3x-1)

simplify

\frac{( \frac{1}{9} x ) ^{2} - 2}{3 x - 1}

\frac{- 162 + x ^{2}}{81 ( 3 x - 1 )}

Solution steps

\frac{( \frac{1}{9} x ) ^{2} - 2}{3 x - 1}

Simplify

(\frac{1}{9} x)^{2} - 2 : \frac{- 162 + x ^{2}}{81}

= \frac{\frac{- 162 + x ^{2}}{81}}{3 x - 1}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{- 162 + x ^{2}}{81 ( 3 x - 1 )}

\frac{( 36 x ^{4} + 30 x ^{3} + 36 x ^{2} )}{( 6 x ^{3} )}

t^{2} - e^{- 2} t + cosh^{2} (t)

2 m \cdot (- m^{2} - m + 5)

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\frac{tan ^{5} ( x )}{sin ^{2} ( x )}

What is ((1/9 x)^2-2)/(3x-1) ?
The solution to ((1/9 x)^2-2)/(3x-1) is (-162+x^2)/(81(3x-1))