What is [ 1/4*a-1/2*b+1]^2 ?

The solution to [ 1/4*a-1/2*b+1]^2 is (-ab+b^2)/4+(a^2)/(16)+a/2-b+1

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simplify [ 1/4a-1/2b+1]^2

simplify

[\frac{1}{4} \cdot a - \frac{1}{2} \cdot b + 1]^{2}

\frac{- ab + b ^{2}}{4} + \frac{a ^{2}}{16} + \frac{a}{2} - b + 1

Solution steps

(\frac{1}{4} a - \frac{1}{2} b + 1)^{2}

\frac{1}{4} a = \frac{a}{4}

\frac{1}{2} b = \frac{b}{2}

= (\frac{a}{4} - \frac{b}{2} + 1)^{2}

(\frac{a}{4} - \frac{b}{2} + 1)^{2} = (\frac{a}{4} - \frac{b}{2} + 1) (\frac{a}{4} - \frac{b}{2} + 1)

= (\frac{a}{4} + 1 - \frac{b}{2}) (\frac{a}{4} + 1 - \frac{b}{2})

Expand

(\frac{a}{4} - \frac{b}{2} + 1) (\frac{a}{4} - \frac{b}{2} + 1) : \frac{- ab + b ^{2}}{4} + \frac{a ^{2}}{16} + \frac{a}{2} - b + 1

= \frac{- ab + b ^{2}}{4} + \frac{a ^{2}}{16} + \frac{a}{2} - b + 1

(8 x^{3})^{\frac{1}{3}}

\frac{( x - y ) ^{5}}{( y - x ) ^{5}}

\frac{( \frac{( x ^{2} + 3 )}{4} ) ^{2} - ( x ^{3} + x )}{2}

- \frac{7}{8} \cdot a^{2} \cdot b^{5} \cdot \frac{c ^{8}}{( - \frac{5}{2} )} \cdot a \cdot b^{5} \cdot c^{6}

8 y + y

What is [ 1/4*a-1/2*b+1]^2 ?
The solution to [ 1/4*a-1/2*b+1]^2 is (-ab+b^2)/4+(a^2)/(16)+a/2-b+1