What is (6^{3x})/((2^{3x))*9^{-2x}} ?

The solution to (6^{3x})/((2^{3x))*9^{-2x}} is 2187^x

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simplify (6^{3x})/((2^{3x))*9^{-2x}}

simplify

\frac{6 ^{3 x}}{( 2 ^{3 x} ) \cdot 9 ^{- 2 x}}

218 7^{x}

Solution steps

\frac{6 ^{3 x}}{( 2 ^{3 x} ) \cdot 9 ^{- 2 x}}

Apply rule:

(a) = a

(2^{3 x}) = 2^{3 x}

= \frac{6 ^{3 x}}{2 ^{3 x} \cdot 9 ^{- 2 x}}

Factor

6^{3 x} : 2^{3 x} \cdot 3^{3 x}

= \frac{2 ^{3 x} \cdot 3 ^{3 x}}{2 ^{3 x} \cdot 9 ^{- 2 x}}

Cancel the common factor:

2^{3 x}

= \frac{3 ^{3 x}}{9 ^{- 2 x}}

Factor

9^{- 2 x} : 3^{- 4 x}

= \frac{3 ^{3 x}}{3 ^{- 4 x}}

Simplify

\frac{3 ^{3 x}}{3 ^{- 4 x}} : 3^{7 x}

= 3^{7 x}

Simplify

3^{7 x} : 218 7^{x}

= 218 7^{x}

27 g^{3} - h^{3}

\frac{7}{7} x - 5 + \frac{1}{7} x + 6

3 a (3 a + 2 c) - 4 b (b + c)

- 4 an - 1 - 3 an - 2 + 10 n^{2} - 2 n + 3

\frac{( ( 1 - 3 x ) ( 4 - x ) )}{( x )}

What is (6^{3x})/((2^{3x))*9^{-2x}} ?
The solution to (6^{3x})/((2^{3x))*9^{-2x}} is 2187^x