What is expand (3a^3+8b^4)^3 ?

The solution to expand (3a^3+8b^4)^3 is 27a^9+216a^6b^4+576a^3b^8+512b^{12}

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expand (3a^3+8b^4)^3

expand

(3 a^{3} + 8 b^{4})^{3}

27 a^{9} + 216 a^{6} b^{4} + 576 a^{3} b^{8} + 512 b^{12}

Solution steps

(3 a^{3} + 8 b^{4})^{3}

Apply Perfect Cube Formula:

(a + b)^{3} = a^{3} + 3 a^{2} b + 3 a b^{2} + b^{3}

(3 a^{3} + 8 b^{4})^{3} = (3 a^{3})^{3} + 3 (3 a^{3})^{2} \cdot 8 b^{4} + 3 \cdot 3 a^{3} (8 b^{4})^{2} + (8 b^{4})^{3}

= (3 a^{3})^{3} + 3 (3 a^{3})^{2} \cdot 8 b^{4} + 3 \cdot 3 a^{3} (8 b^{4})^{2} + (8 b^{4})^{3}

Simplify

(3 a^{3})^{3} + 3 (3 a^{3})^{2} \cdot 8 b^{4} + 3 \cdot 3 a^{3} (8 b^{4})^{2} + (8 b^{4})^{3} : 27 a^{9} + 216 a^{6} b^{4} + 576 a^{3} b^{8} + 512 b^{12}

= 27 a^{9} + 216 a^{6} b^{4} + 576 a^{3} b^{8} + 512 b^{12}

lo g_{10} (y) (y - 1)

9 a^{4} - x^{4}

\frac{sin ^{2} ( 2 x )}{sin ^{2} ( x )}

x (x^{\frac{1}{2}} - x)^{- 2}

a^{4} b^{4} - 16

What is expand (3a^3+8b^4)^3 ?
The solution to expand (3a^3+8b^4)^3 is 27a^9+216a^6b^4+576a^3b^8+512b^{12}