What is \sqrt[6]{64}a^{18}b^6c^{-1}2 ?

The solution to \sqrt[6]{64}a^{18}b^6c^{-1}2 is (4a^{18}b^6)/c

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simplify \sqrt[6]{64}a^{18}b^6c^{-1}2

simplify

\frac{4 a ^{18} b ^{6}}{c}

Solution steps

= 2 a^{18} b^{6} c^{- 1} \cdot 2

Multiply the numbers:

2 \cdot 2 = 4

= 4 a^{18} b^{6} c^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

c^{- 1} = \frac{1}{c}

= 4 a^{18} b^{6} \frac{1}{c}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{4 a ^{18} b ^{6} \cdot 1}{c}

Multiply the numbers:

4 \cdot 1 = 4

= \frac{4 a ^{18} b ^{6}}{c}

\frac{( x \cdot 14 + ( 100 - x ) \cdot 15 )}{100}

(9 x^{3} \cdot y \cdot 10 x^{3} + 8 x^{2} - 5) - (7 + 10 x^{3} - 4 x^{3} \cdot y)

(2 a^{2} b^{3}) (- 3 a^{- 4} b^{12})^{0}

c - \frac{b ^{2}}{4} a

d - \frac{\frac{4}{5}}{( - 3 )}

What is \sqrt[6]{64}a^{18}b^6c^{-1}2 ?
The solution to \sqrt[6]{64}a^{18}b^6c^{-1}2 is (4a^{18}b^6)/c