What is (2a^{-3}b^{-2})^{-3} ?

The solution to (2a^{-3}b^{-2})^{-3} is (a^9b^6)/8

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simplify (2a^{-3}b^{-2})^{-3}

simplify

(2 a^{- 3} b^{- 2})^{- 3}

\frac{a ^{9} b ^{6}}{8}

Solution steps

(2 a^{- 3} b^{- 2})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(2 a^{- 3} b^{- 2})^{- 3} = \frac{1}{( 2 a ^{- 3} b ^{- 2} ) ^{3}}

= \frac{1}{( 2 a ^{- 3} b ^{- 2} ) ^{3}}

Simplify

(2 a^{- 3} b^{- 2})^{3} : \frac{8}{a ^{9} b ^{6}}

= \frac{1}{\frac{8}{a ^{9} b ^{6}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{a ^{9} b ^{6}}{8}

4 lo g_{10} (5^{x})

9 a^{4} - 34 a^{2} \cdot b^{2} + 25 b^{4}

\frac{( x ^{2} - 7 x + 6 )}{( x - 6 )}

q^{2} r^{2} q^{4} r^{5}

(\frac{1}{( 4 3 )})^{n}

What is (2a^{-3}b^{-2})^{-3} ?
The solution to (2a^{-3}b^{-2})^{-3} is (a^9b^6)/8