What is (b^2-b)^2-2(b^2-b) ?

The solution to (b^2-b)^2-2(b^2-b) is b^4-2b^3-b^2+2b

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simplify (b^2-b)^2-2(b^2-b)

simplify

(b^{2} - b)^{2} - 2 (b^{2} - b)

b^{4} - 2 b^{3} - b^{2} + 2 b

Solution steps

(b^{2} - b)^{2} - 2 (b^{2} - b)

Expand

(b^{2} - b)^{2} : b^{4} - 2 b^{3} + b^{2}

= b^{4} - 2 b^{3} + b^{2} - 2 (b^{2} - b)

Expand

- 2 (b^{2} - b) : - 2 b^{2} + 2 b

= b^{4} - 2 b^{3} + b^{2} - 2 b^{2} + 2 b

Add similar elements:

b^{2} - 2 b^{2} = - b^{2}

= b^{4} - 2 b^{3} - b^{2} + 2 b

l^{- 1} \cdot \frac{( s - 2 )}{( ( s - 2 ) ^{7} )}

\frac{1}{2 x ( 7.9 + 4.8 ) \cdot x ^{5.2}}

(b + 8 c)^{3}

2 x^{3} - 11 x^{2} + 13 x - 4

\frac{3 x ^{3} + 3}{3}

What is (b^2-b)^2-2(b^2-b) ?
The solution to (b^2-b)^2-2(b^2-b) is b^4-2b^3-b^2+2b