What is factor a^4-81b^{10} ?

The solution to factor a^4-81b^{10} is (a^2+9b^5)(a^2-9b^5)

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factor a^4-81b^{10}

factor

a^{4} - 81 b^{10}

(a^{2} + 9 b^{5}) (a^{2} - 9 b^{5})

Solution steps

a^{4} - 81 b^{10}

a^{4} = (a^{2})^{2}

81 b^{10} = (9 b^{5})^{2}

= (a^{2})^{2} - (9 b^{5})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(a^{2})^{2} - (9 b^{5})^{2} = (a^{2} + 9 b^{5}) (a^{2} - 9 b^{5})

= (a^{2} + 9 b^{5}) (a^{2} - 9 b^{5})

\frac{( e ^{n} )}{( e ^{2 n} + g )}

\frac{( ( x ^{3} + 4 x ^{2} ) ( 2 x + 4 ) )}{( 2 x ^{2} + 12 x + 16 )}

\frac{a}{b} + 2 \frac{a}{0.5} b

(1 + a^{2})^{3}

\frac{( - 2 x ^{3} - 7 x ^{2} - 14 x )}{( - 7 x )}

What is factor a^4-81b^{10} ?
The solution to factor a^4-81b^{10} is (a^2+9b^5)(a^2-9b^5)