What is ((-2x^3-7x^2-14x))/((-7x)) ?

The solution to ((-2x^3-7x^2-14x))/((-7x)) is (2x^2+7x+14)/7

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simplify ((-2x^3-7x^2-14x))/((-7x))

simplify

\frac{( - 2 x ^{3} - 7 x ^{2} - 14 x )}{( - 7 x )}

\frac{2 x ^{2} + 7 x + 14}{7}

Solution steps

\frac{- 2 x ^{3} - 7 x ^{2} - 14 x}{- 7 x}

Factor

- 2 x^{3} - 7 x^{2} - 14 x : - (2 x^{3} + 7 x^{2} + 14 x)

= \frac{- ( 2 x ^{3} + 7 x ^{2} + 14 x )}{- 7 x}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{2 x ^{3} + 7 x ^{2} + 14 x}{7 x}

Factor

2 x^{3} + 7 x^{2} + 14 x : x (2 x^{2} + 7 x + 14)

= \frac{x ( 2 x ^{2} + 7 x + 14 )}{7 x}

Cancel the common factor:

x

= \frac{2 x ^{2} + 7 x + 14}{7}

2 x^{4} - 3 x^{3} - 3 x - 2

\frac{( 1 + cos ( x ) )}{sin ( x )}

f (x) 1 x^{3} - 3 x^{2} + 3 x - 5

\frac{49 \cdot z ^{- 3}}{7 ^{- 3} \cdot 10 \cdot z ^{- 5}}

a^{n + 2} - a^{n - 1}

What is ((-2x^3-7x^2-14x))/((-7x)) ?
The solution to ((-2x^3-7x^2-14x))/((-7x)) is (2x^2+7x+14)/7