What is factor 2x^4-3x^3-3x-2 ?

The solution to factor 2x^4-3x^3-3x-2 is (2x+1)(x-2)(x^2+1)

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factor 2x^4-3x^3-3x-2

factor

2 x^{4} - 3 x^{3} - 3 x - 2

(2 x + 1) (x - 2) (x^{2} + 1)

Solution steps

2 x^{4} - 3 x^{3} - 3 x - 2

Use the rational root theorem

= (2 x + 1) \frac{2 x ^{4} - 3 x ^{3} - 3 x - 2}{2 x + 1}

\frac{2 x ^{4} - 3 x ^{3} - 3 x - 2}{2 x + 1} = x^{3} - 2 x^{2} + x - 2

= (2 x + 1) (x^{3} - 2 x^{2} + x - 2)

Factor

x^{3} - 2 x^{2} + x - 2 : (x - 2) (x^{2} + 1)

= (2 x + 1) (x - 2) (x^{2} + 1)

\frac{( 1 + cos ( x ) )}{sin ( x )}

f (x) 1 x^{3} - 3 x^{2} + 3 x - 5

\frac{49 \cdot z ^{- 3}}{7 ^{- 3} \cdot 10 \cdot z ^{- 5}}

a^{n + 2} - a^{n - 1}

4 x^{5} - 9 x^{3} y^{2}

What is factor 2x^4-3x^3-3x-2 ?
The solution to factor 2x^4-3x^3-3x-2 is (2x+1)(x-2)(x^2+1)