What is 7^2x+3-49^x+2/(343^{n+1)} 2/3 ?

The solution to 7^2x+3-49^x+2/(343^{n+1)} 2/3 is 49x+3-49^x+4/(3*343^{n+1)}

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simplify 7^2x+3-49^x+2/(343^{n+1)} 2/3

simplify

7^{2} x + 3 - 4 9^{x} + \frac{2}{34 3 ^{n + 1}} \frac{2}{3}

49 x + 3 - 4 9^{x} + \frac{4}{3 \cdot 34 3 ^{n + 1}}

Solution steps

7^{2} x + 3 - 4 9^{x} + \frac{2}{34 3 ^{n + 1}} \cdot \frac{2}{3}

7^{2} = 49

\frac{2}{34 3 ^{n + 1}} \cdot \frac{2}{3} = \frac{4}{34 3 ^{n + 1} \cdot 3}

= 49 x + 3 - 4 9^{x} + \frac{4}{34 3 ^{n + 1} \cdot 3}

= 49 x + 3 - 4 9^{x} + \frac{4}{3 \cdot 34 3 ^{n + 1}}

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What is 7^2x+3-49^x+2/(343^{n+1)} 2/3 ?
The solution to 7^2x+3-49^x+2/(343^{n+1)} 2/3 is 49x+3-49^x+4/(3*343^{n+1)}