What is factor 4a^2-4a*b^2+b^4 ?

The solution to factor 4a^2-4a*b^2+b^4 is (2a-b^2)^2

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factor 4a^2-4a*b^2+b^4

factor

4 a^{2} - 4 a \cdot b^{2} + b^{4}

(2 a - b^{2})^{2}

Solution steps

4 a^{2} - 4 a b^{2} + b^{4}

Break the expression into groups

= (4 a^{2} - 2 a b^{2}) + (- 2 a b^{2} + b^{4})

Factor out

2 a

from

4 a^{2} - 2 a b^{2} : 2 a (2 a - b^{2})

Factor out

- b^{2}

from

- 2 a b^{2} + b^{4} : - b^{2} (2 a - b^{2})

= 2 a (2 a - b^{2}) - b^{2} (2 a - b^{2})

Factor out common term

2 a - b^{2}

= (2 a - b^{2}) (2 a - b^{2})

Apply exponent rule:

aa = a^{2}

(2 a - b^{2}) (2 a - b^{2}) = (2 a - b^{2})^{2}

= (2 a - b^{2})^{2}

(a^{2} + 5 a + 2) (0.5 a)

\frac{( 8 x ^{3} y ^{- 4} )}{( 2 x ^{5} y ^{2} )}

2 x^{5} - x^{4} - 10 x^{3} + 5 x^{2} + 8 x - 4

63 a - 70

(x^{3} y^{2} z^{3})^{\frac{1}{13}}

What is factor 4a^2-4a*b^2+b^4 ?
The solution to factor 4a^2-4a*b^2+b^4 is (2a-b^2)^2