What is factor 81x^4-9x^2+6x-1 ?

The solution to factor 81x^4-9x^2+6x-1 is (9x^2+3x-1)(9x^2-3x+1)

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factor 81x^4-9x^2+6x-1

factor

81 x^{4} - 9 x^{2} + 6 x - 1

(9 x^{2} + 3 x - 1) (9 x^{2} - 3 x + 1)

Solution steps

81 x^{4} - 9 x^{2} + 6 x - 1

Factor

- 9 x^{2} + 6 x - 1 : - (3 x - 1)^{2}

= 81 x^{4} - (3 x - 1)^{2}

Simplify

81 x^{4} : (9 x^{2})^{2}

= (9 x^{2})^{2} - (3 x - 1)^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(9 x^{2})^{2} - (3 x - 1)^{2} = (9 x^{2} + (3 x - 1)) (9 x^{2} - (3 x - 1))

= (9 x^{2} + (3 x - 1)) (9 x^{2} - (3 x - 1))

Simplify

(9 x^{2} + (3 x - 1)) (9 x^{2} - (3 x - 1)) : (9 x^{2} + 3 x - 1) (9 x^{2} - 3 x + 1)

= (9 x^{2} + 3 x - 1) (9 x^{2} - 3 x + 1)

x^{4} + 12 x^{2} y^{2} + 64 y^{4}

\frac{- 8}{25 x - 50}

(1 + 2 x + y)^{2}

(\frac{1}{5 \cdot a ^{3} + b ^{2}})^{2}

(a + b) (a - b) + (\frac{a - 1}{2 b})^{2}

What is factor 81x^4-9x^2+6x-1 ?
The solution to factor 81x^4-9x^2+6x-1 is (9x^2+3x-1)(9x^2-3x+1)