What is (a+b)(a-b)+((a-1)/(2b))^2 ?

The solution to (a+b)(a-b)+((a-1)/(2b))^2 is a^2-b^2+((a-1)^2)/(4b^2)

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simplify (a+b)(a-b)+((a-1)/(2b))^2

simplify

(a + b) (a - b) + (\frac{a - 1}{2 b})^{2}

a^{2} - b^{2} + \frac{( a - 1 ) ^{2}}{4 b ^{2}}

Solution steps

(a + b) (a - b) + (\frac{a - 1}{2 b})^{2}

Simplify

(\frac{a - 1}{2 b})^{2} : \frac{( a - 1 ) ^{2}}{4 b ^{2}}

= (a + b) (a - b) + \frac{( a - 1 ) ^{2}}{4 b ^{2}}

Expand

(a + b) (a - b) : a^{2} - b^{2}

= a^{2} - b^{2} + \frac{( a - 1 ) ^{2}}{4 b ^{2}}

z^{3} + 2 z^{2} - 68 z + 120

(7 n^{5} p^{3})^{4}

e^{x} \cdot ln (x^{2})

\frac{tan ^{2} ( x )}{sec ^{5} ( x )}

i^{3} + j^{3} + k^{3}

What is (a+b)(a-b)+((a-1)/(2b))^2 ?
The solution to (a+b)(a-b)+((a-1)/(2b))^2 is a^2-b^2+((a-1)^2)/(4b^2)