What is (1^4(x^2)^2+3^3-2^5)/4 ?

The solution to (1^4(x^2)^2+3^3-2^5)/4 is (x^4-5)/4

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simplify (1^4(x^2)^2+3^3-2^5)/4

simplify

\frac{1 ^{4} ( x ^{2} ) ^{2} + 3 ^{3} - 2 ^{5}}{4}

\frac{x ^{4} - 5}{4}

Solution steps

\frac{1 ^{4} ( x ^{2} ) ^{2} + 3 ^{3} - 2 ^{5}}{4}

1^{4} (x^{2})^{2} = x^{4}

3^{3} = 27

2^{5} = 32

= \frac{x ^{4} + 27 - 32}{4}

Subtract the numbers:

27 - 32 = - 5

= \frac{x ^{4} - 5}{4}

36 x^{2} - 24 x \cdot y^{2} + 4 y^{4}

- 18 a - 27 c

(- y)^{7}

a ⎩ ⎨ ⎧ \frac{24 a ^{4} \cdot b ^{3}}{( 2 a ^{2} \cdot b )} ⎭ ⎬ ⎫^{\frac{3}{2}}

\frac{( 20 x ^{3} + 40 x ^{5} )}{( 5 x ^{2} + 4 x ^{3} )}

What is (1^4(x^2)^2+3^3-2^5)/4 ?
The solution to (1^4(x^2)^2+3^3-2^5)/4 is (x^4-5)/4