What is ((20x^3+40x^5))/((5x^2+4x^3)) ?

The solution to ((20x^3+40x^5))/((5x^2+4x^3)) is (20x(1+2x^2))/(5+4x)

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simplify ((20x^3+40x^5))/((5x^2+4x^3))

simplify

\frac{( 20 x ^{3} + 40 x ^{5} )}{( 5 x ^{2} + 4 x ^{3} )}

\frac{20 x ( 1 + 2 x ^{2} )}{5 + 4 x}

Solution steps

\frac{20 x ^{3} + 40 x ^{5}}{5 x ^{2} + 4 x ^{3}}

Factor

20 x^{3} + 40 x^{5} : 20 x^{3} (1 + 2 x^{2})

= \frac{20 x ^{3} ( 1 + 2 x ^{2} )}{5 x ^{2} + 4 x ^{3}}

Factor

5 x^{2} + 4 x^{3} : x^{2} (5 + 4 x)

= \frac{20 x ^{3} ( 1 + 2 x ^{2} )}{x ^{2} ( 5 + 4 x )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{3} = x^{2} x

= \frac{20 x ^{2} x ( 1 + 2 x ^{2} )}{x ^{2} ( 5 + 4 x )}

Cancel the common factor:

x^{2}

= \frac{20 x ( 1 + 2 x ^{2} )}{5 + 4 x}

\frac{( 2 b - 4 )}{( b ^{3} + 8 ) + ( 1 ) ( b + 2 )}

\frac{( 33.3 \cdot 1 0 ^{- 3} - x )}{( ( x ) ( x ) )}

5.1 (1 - x)^{2}

a^{2} - 1 - 2 x - x^{2}

3 x - 2 x^{4} y

What is ((20x^3+40x^5))/((5x^2+4x^3)) ?
The solution to ((20x^3+40x^5))/((5x^2+4x^3)) is (20x(1+2x^2))/(5+4x)