What is (x^2-3x)(x^2-3x-1)-20 ?

The solution to (x^2-3x)(x^2-3x-1)-20 is x^4-6x^3+8x^2+3x-20

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simplify (x^2-3x)(x^2-3x-1)-20

simplify

(x^{2} - 3 x) (x^{2} - 3 x - 1) - 20

x^{4} - 6 x^{3} + 8 x^{2} + 3 x - 20

Solution steps

(x^{2} - 3 x) (x^{2} - 3 x - 1) - 20

Distribute parentheses

= x^{2} x^{2} + x^{2} (- 3 x) + x^{2} (- 1) - 3 x x^{2} - 3 x (- 3 x) - 3 x (- 1) - 20

Simplify

x^{2} x^{2} + x^{2} (- 3 x) + x^{2} (- 1) - 3 x x^{2} - 3 x (- 3 x) - 3 x (- 1) : x^{4} - 6 x^{3} + 8 x^{2} + 3 x

= x^{4} - 6 x^{3} + 8 x^{2} + 3 x - 20

\frac{( x ^{3} - 4 - x + 4 x ^{2} )}{( x ^{2} + 3 x - 4 )}

x^{3} + 2 x^{2} y - x y^{2} - 2 y^{3}

\frac{( 2 x ^{33} x ^{2} - 1 )}{( x ^{1} )}

\frac{( 2 - i ) \cdot ( z + 4 i )}{- 3 + i}

5 x y^{2} + 4 y^{2} x

What is (x^2-3x)(x^2-3x-1)-20 ?
The solution to (x^2-3x)(x^2-3x-1)-20 is x^4-6x^3+8x^2+3x-20