What is ((4(x+1)))/7+((x+3))/7-((2(x+5)))/7 ?

The solution to ((4(x+1)))/7+((x+3))/7-((2(x+5)))/7 is (3x-3)/7

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simplify ((4(x+1)))/7+((x+3))/7-((2(x+5)))/7

simplify

\frac{( 4 ( x + 1 ) )}{7} + \frac{( x + 3 )}{7} - \frac{( 2 ( x + 5 ) )}{7}

\frac{3 x - 3}{7}

Solution steps

\frac{4 ( x + 1 )}{7} + \frac{x + 3}{7} - \frac{2 ( x + 5 )}{7}

Join

\frac{4 ( x + 1 )}{7} + \frac{x + 3}{7} - \frac{2 ( x + 5 )}{7} : \frac{4 ( x + 1 ) + x + 3 - 2 ( x + 5 )}{7}

= \frac{4 ( x + 1 ) + x + 3 - 2 ( x + 5 )}{7}

Expand

4 (x + 1) + x + 3 - 2 (x + 5) : 3 x - 3

= \frac{3 x - 3}{7}

\frac{( 2 x ^{2} + 13 x + 6 )}{( 2 x + 1 )}

(2.3) 4 \cdot 53 8^{3} (x + y - 7)

x^{2} + 4 x + 4 - y^{2}

4 x^{2} + 4^{2} - 12 x + 8 y + j

(3 z)^{4} - z^{7}

What is ((4(x+1)))/7+((x+3))/7-((2(x+5)))/7 ?
The solution to ((4(x+1)))/7+((x+3))/7-((2(x+5)))/7 is (3x-3)/7