What is ((2x+3*2-6x+9/4 x^2-99-x^2+12x-3))/(12x) ?

The solution to ((2x+3*2-6x+9/4 x^2-99-x^2+12x-3))/(12x) is (32x+5x^2-384)/(48x)

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simplify ((2x+3*2-6x+9/4 x^2-99-x^2+12x-3))/(12x)

simplify

\frac{( 2 x + 3 \cdot 2 - 6 x + \frac{9}{4} x ^{2} - 99 - x ^{2} + 12 x - 3 )}{12 x}

\frac{32 x + 5 x ^{2} - 384}{48 x}

Solution steps

\frac{2 x + 3 \cdot 2 - 6 x + \frac{9}{4} x ^{2} - 99 - x ^{2} + 12 x - 3}{12 x}

Simplify

2 x + 3 \cdot 2 - 6 x + \frac{9}{4} x^{2} - 99 - x^{2} + 12 x - 3 : \frac{32 x + 5 x ^{2} - 384}{4}

= \frac{\frac{32 x + 5 x ^{2} - 384}{4}}{12 x}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{32 x + 5 x ^{2} - 384}{4 \cdot 12 x}

Multiply the numbers:

4 \cdot 12 = 48

= \frac{32 x + 5 x ^{2} - 384}{48 x}

p^{2} q^{2} - 64 a^{4}

(a^{5})^{6}

16 + 4 k^{2}

2 m^{3} + 26 m^{2} + 64 m + 40

1 + \frac{( 2 b )}{3} + \frac{( b ^{2} )}{9}

What is ((2x+3*2-6x+9/4 x^2-99-x^2+12x-3))/(12x) ?
The solution to ((2x+3*2-6x+9/4 x^2-99-x^2+12x-3))/(12x) is (32x+5x^2-384)/(48x)