What is 1+((2b))/3+((b^2))/9 ?

The solution to 1+((2b))/3+((b^2))/9 is (9+6b+b^2)/9

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simplify 1+((2b))/3+((b^2))/9

simplify

1 + \frac{( 2 b )}{3} + \frac{( b ^{2} )}{9}

\frac{9 + 6 b + b ^{2}}{9}

Solution steps

1 + \frac{2 b}{3} + \frac{b ^{2}}{9}

Join

\frac{2 b}{3} + \frac{b ^{2}}{9} : \frac{6 b + b ^{2}}{9}

= 1 + \frac{6 b + b ^{2}}{9}

Apply the fraction rule:

1 + \frac{b}{c} = \frac{c + b}{c}

= \frac{9 + 6 b + b ^{2}}{9}

(\frac{2 b ^{4}}{3 a ^{2} b ^{6}})^{4}

- 3 (w + 5) + 6 w

5 a^{2} b^{4} - 9 a^{4} b^{2}

\frac{( x ^{n + 1} )}{( n + 1 )}

\frac{( x - 2 )}{( x + 3 )} \frac{( x + 1 )}{x}

What is 1+((2b))/3+((b^2))/9 ?
The solution to 1+((2b))/3+((b^2))/9 is (9+6b+b^2)/9