What is factor p^2+p^8 ?

The solution to factor p^2+p^8 is p^2(p^2+1)(p^4-p^2+1)

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factor p^2+p^8

factor

p^{2} + p^{8}

p^{2} (p^{2} + 1) (p^{4} - p^{2} + 1)

Solution steps

p^{2} + p^{8}

Write in the standard form

= p^{8} + p^{2}

Factor out common term

p^{2} : p^{2} (p^{6} + 1)

= p^{2} (p^{6} + 1)

Factor

p^{6} + 1 : (p^{2} + 1) (p^{4} - p^{2} + 1)

= p^{2} (p^{2} + 1) (p^{4} - p^{2} + 1)

7 h^{2} + 2 h + 5 - h^{2} + h

\frac{z z _{5} ( z + 2 )}{z + 2}

(p^{1} + p^{2}) lo g_{10} (p^{1} + p^{2})

\frac{( 4 ) x ^{2} + ( 2 x )}{( x ) + 6}

8 x y + 12 x

What is factor p^2+p^8 ?
The solution to factor p^2+p^8 is p^2(p^2+1)(p^4-p^2+1)