What is (p^1+p^2)log_{10}(p^1+p^2) ?

The solution to (p^1+p^2)log_{10}(p^1+p^2) is (p+p^2)log_{10}(p+p^2)

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simplify (p^1+p^2)log_{10}(p^1+p^2)

simplify

(p^{1} + p^{2}) lo g_{10} (p^{1} + p^{2})

(p + p^{2}) lo g_{10} (p + p^{2})

Solution steps

(p^{1} + p^{2}) lo g_{10} (p^{1} + p^{2})

Apply rule

a^{1} = a

p^{1} = p

= (p^{1} + p^{2}) lo g_{10} (p + p^{2})

Apply exponent rule:

a^{1} = a

p^{1} = p

= (p + p^{2}) lo g_{10} (p + p^{2})

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What is (p^1+p^2)log_{10}(p^1+p^2) ?
The solution to (p^1+p^2)log_{10}(p^1+p^2) is (p+p^2)log_{10}(p+p^2)