What is (9c^{-9})^{-3} ?

The solution to (9c^{-9})^{-3} is (c^{27})/(729)

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simplify (9c^{-9})^{-3}

simplify

(9 c^{- 9})^{- 3}

\frac{c ^{27}}{729}

Solution steps

(9 c^{- 9})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(9 c^{- 9})^{- 3} = \frac{1}{( 9 c ^{- 9} ) ^{3}}

= \frac{1}{( 9 c ^{- 9} ) ^{3}}

Simplify

(9 c^{- 9})^{3} : \frac{729}{c ^{27}}

= \frac{1}{\frac{729}{c ^{27}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{c ^{27}}{729}

a^{- 1} + 1

\frac{9 x ^{2} - 1}{6 x ^{2} + 5 x + 1}

(\frac{1 - 1}{x ^{2}})^{- 1}

6 x^{10} - 96 x^{2}

4 x y^{2} - 7 x^{2} y + 12 x^{2} y - 6 x y^{2} + (- 3) x^{2} y + 5 x y^{2}