What is (9x^2-1)/(6x^2+5x+1) ?

The solution to (9x^2-1)/(6x^2+5x+1) is (3x-1)/(2x+1)

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simplify (9x^2-1)/(6x^2+5x+1)

simplify

\frac{9 x ^{2} - 1}{6 x ^{2} + 5 x + 1}

\frac{3 x - 1}{2 x + 1}

Solution steps

\frac{9 x ^{2} - 1}{6 x ^{2} + 5 x + 1}

Factor

9 x^{2} - 1 : (3 x + 1) (3 x - 1)

= \frac{( 3 x + 1 ) ( 3 x - 1 )}{6 x ^{2} + 5 x + 1}

Factor

6 x^{2} + 5 x + 1 : (3 x + 1) (2 x + 1)

= \frac{( 3 x + 1 ) ( 3 x - 1 )}{( 3 x + 1 ) ( 2 x + 1 )}

Cancel the common factor:

3 x + 1

= \frac{3 x - 1}{2 x + 1}

(\frac{1 - 1}{x ^{2}})^{- 1}

6 x^{10} - 96 x^{2}

4 x y^{2} - 7 x^{2} y + 12 x^{2} y - 6 x y^{2} + (- 3) x^{2} y + 5 x y^{2}

p_{-} (n + 1) (x)

10 x^{3} - 19 x^{2} - 61 x - 8

What is (9x^2-1)/(6x^2+5x+1) ?
The solution to (9x^2-1)/(6x^2+5x+1) is (3x-1)/(2x+1)