What is log_{10}(((x^2+x+1))/((x^2-x+1))) ?

The solution to log_{10}(((x^2+x+1))/((x^2-x+1))) is log_{10}(x^2+x+1)-log_{10}(x^2-x+1)

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simplify log_{10}(((x^2+x+1))/((x^2-x+1)))

simplify

lo g_{10} (\frac{( x ^{2} + x + 1 )}{( x ^{2} - x + 1 )})

lo g_{10} (x^{2} + x + 1) - lo g_{10} (x^{2} - x + 1)

Solution steps

lo g_{10} (\frac{x ^{2} + x + 1}{x ^{2} - x + 1})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{x ^{2} + x + 1}{x ^{2} - x + 1}) = lo g_{10} (x^{2} + x + 1) - lo g_{10} (x^{2} - x + 1)

= lo g_{10} (x^{2} + x + 1) - lo g_{10} (x^{2} - x + 1)

x^{4} + 3 x^{3} + 3 x^{2} - 1

(- x^{6} \cdot y^{8})^{2}

\frac{( m )}{91 - 8809674712}

4 x (x + 5) - x (x + 5)

\frac{1}{( 1 + x ^{2} + 1 )}

What is log_{10}(((x^2+x+1))/((x^2-x+1))) ?
The solution to log_{10}(((x^2+x+1))/((x^2-x+1))) is log_{10}(x^2+x+1)-log_{10}(x^2-x+1)