What is a^2+1/(a^2)-2-3a+3/a ?

The solution to a^2+1/(a^2)-2-3a+3/a is (a^4+1+3a-2a^2-3a^3)/(a^2)

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simplify a^2+1/(a^2)-2-3a+3/a

simplify

a^{2} + \frac{1}{a ^{2}} - 2 - 3 a + \frac{3}{a}

\frac{a ^{4} + 1 + 3 a - 2 a ^{2} - 3 a ^{3}}{a ^{2}}

Solution steps

a^{2} + \frac{1}{a ^{2}} - 2 - 3 a + \frac{3}{a}

Join

\frac{1}{a ^{2}} + \frac{3}{a} : \frac{1 + 3 a}{a ^{2}}

= a^{2} + \frac{1 + 3 a}{a ^{2}} - 2 - 3 a

Convert

a^{2}

to fraction

: \frac{a ^{4}}{a ^{2}}

Convert

2

to fraction

: \frac{2 a ^{2}}{a ^{2}}

Convert

3 a

to fraction

: \frac{3 a ^{3}}{a ^{2}}

= \frac{a ^{4}}{a ^{2}} + \frac{1 + 3 a}{a ^{2}} - \frac{2 a ^{2}}{a ^{2}} - \frac{3 a ^{3}}{a ^{2}}

Apply the fraction rule:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{a ^{4} + 1 + 3 a - 2 a ^{2} - 3 a ^{3}}{a ^{2}}

12 \cdot \frac{( a ^{2} )}{( b ^{2} )} + \frac{a}{b} - 20

(\frac{3}{2 y - 1})^{3}

sec (x) - sin^{2} (x) sec (x)

\frac{2 x ^{2} - 18}{2 x ^{2} - 8 x + 6}

9 x^{4} - 25 x^{2} y^{2} + 16 y^{4}

What is a^2+1/(a^2)-2-3a+3/a ?
The solution to a^2+1/(a^2)-2-3a+3/a is (a^4+1+3a-2a^2-3a^3)/(a^2)