What is x^2+1/((x^2))+2-2x-2/x ?

The solution to x^2+1/((x^2))+2-2x-2/x is (x^4+1-2x+2x^2-2x^3)/(x^2)

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simplify x^2+1/((x^2))+2-2x-2/x

simplify

x^{2} + \frac{1}{( x ^{2} )} + 2 - 2 x - \frac{2}{x}

\frac{x ^{4} + 1 - 2 x + 2 x ^{2} - 2 x ^{3}}{x ^{2}}

Solution steps

x^{2} + \frac{1}{x ^{2}} + 2 - 2 x - \frac{2}{x}

Join

\frac{1}{x ^{2}} - \frac{2}{x} : \frac{1 - 2 x}{x ^{2}}

= x^{2} + \frac{1 - 2 x}{x ^{2}} + 2 - 2 x

Convert

x^{2}

to fraction

: \frac{x ^{4}}{x ^{2}}

Convert

2

to fraction

: \frac{2 x ^{2}}{x ^{2}}

Convert

2 x

to fraction

: \frac{2 x ^{3}}{x ^{2}}

= \frac{x ^{4}}{x ^{2}} + \frac{1 - 2 x}{x ^{2}} + \frac{2 x ^{2}}{x ^{2}} - \frac{2 x ^{3}}{x ^{2}}

Apply the fraction rule:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{x ^{4} + 1 - 2 x + 2 x ^{2} - 2 x ^{3}}{x ^{2}}

(a + b)^{3} - 16 (a + b)

(1 + x)^{- 2} + (1 + x)^{- 4}

\frac{9}{x} - \frac{8}{t}

(3 a + 4 z)^{7}

9 c^{0} (0.8)^{0} (1 - 0.6)^{9}

What is x^2+1/((x^2))+2-2x-2/x ?
The solution to x^2+1/((x^2))+2-2x-2/x is (x^4+1-2x+2x^2-2x^3)/(x^2)