What is factor y^4-81x^4 ?

The solution to factor y^4-81x^4 is (y^2+9x^2)(y+3x)(y-3x)

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factor y^4-81x^4

factor

y^{4} - 81 x^{4}

(y^{2} + 9 x^{2}) (y + 3 x) (y - 3 x)

Solution steps

y^{4} - 81 x^{4}

y^{4} = (y^{2})^{2}

81 x^{4} = (9 x^{2})^{2}

= (y^{2})^{2} - (9 x^{2})^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(y^{2})^{2} - (9 x^{2})^{2} = (y^{2} + 9 x^{2}) (y^{2} - 9 x^{2})

= (y^{2} + 9 x^{2}) (y^{2} - 9 x^{2})

Factor

y^{2} - 9 x^{2} : (y + 3 x) (y - 3 x)

= (y^{2} + 9 x^{2}) (y + 3 x) (y - 3 x)

f (x) = 3 + 4 x^{5}

(a^{2} + 1)^{2} + (a^{2} + 5)^{2} - 4 \cdot (a^{2} + 3)^{2}

17 x^{3} + (3 x + 8 x^{3})

(14.5 - 5.3) \cdot x^{2.5} + (3.5) 2

\frac{( x ^{3} - 49 x )}{( x ^{4} - 7 x ^{3} )}

What is factor y^4-81x^4 ?
The solution to factor y^4-81x^4 is (y^2+9x^2)(y+3x)(y-3x)