What is (x-1)((x-5)/4)((x+1)/4) ?

The solution to (x-1)((x-5)/4)((x+1)/4) is ((x-1)(x-5)(x+1))/(16)

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simplify (x-1)((x-5)/4)((x+1)/4)

simplify

(x - 1) (\frac{x - 5}{4}) (\frac{x + 1}{4})

\frac{( x - 1 ) ( x - 5 ) ( x + 1 )}{16}

Solution steps

(x - 1) (\frac{x - 5}{4}) (\frac{x + 1}{4})

Simplify

(x - 1) (\frac{x - 5}{4}) (\frac{x + 1}{4}) : (x - 1) \frac{x - 5}{4} \cdot \frac{x + 1}{4}

= (x - 1) \frac{x - 5}{4} \cdot \frac{x + 1}{4}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{( x - 1 ) ( x - 5 ) ( x + 1 )}{4 \cdot 4}

Multiply the numbers:

4 \cdot 4 = 16

= \frac{( x - 1 ) ( x - 5 ) ( x + 1 )}{16}

6.626 x 1 0^{- 3} 4 \cdot 3 x 1 0^{8}

\frac{1}{3} \cdot (x + 15) + \frac{2}{3} \cdot (x + 9)

1.5 a - a + 7 - 9.5 a

(x^{2} + 18)^{2}

(\frac{x ^{2} - 1}{( x ^{2} )})^{4}

What is (x-1)((x-5)/4)((x+1)/4) ?
The solution to (x-1)((x-5)/4)((x+1)/4) is ((x-1)(x-5)(x+1))/(16)