What are the solutions to the equation -4.9t^2=9.8t^2+19.6t-9.8 ?

The solutions to the equation -4.9t^2=9.8t^2+19.6t-9.8 are t=(-2+sqrt(10))/3 ,t=-(2+sqrt(10))/3

Find the zeros of -4.9t^2=9.8t^2+19.6t-9.8

The zeros of -4.9t^2=9.8t^2+19.6t-9.8 are t=(-2+sqrt(10))/3 ,t=-(2+sqrt(10))/3

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- 4.9 t^{2} = 9.8 t^{2} + 19.6 t - 9.8

t = \frac{- 2 + 10}{3}, t = - \frac{2 + 10}{3}

Solution steps

- 4.9 t^{2} = 9.8 t^{2} + 19.6 t - 9.8

Multiply both sides by

10

- 49 t^{2} = 98 t^{2} + 196 t - 98

Switch sides

98 t^{2} + 196 t - 98 = - 49 t^{2}

Move

49 t^{2}

to the left side

147 t^{2} + 196 t - 98 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 196 \pm 19 6 ^{2} - 4 \cdot 147 ( - 98 )}{2 \cdot 147}

19 6^{2} - 4 \cdot 147 (- 98) = 9810

t_{1, 2} = \frac{- 196 \pm 98 10}{2 \cdot 147}

Separate the solutions

t_{1} = \frac{- 196 + 98 10}{2 \cdot 147}, t_{2} = \frac{- 196 - 98 10}{2 \cdot 147}

t = \frac{- 196 + 98 10}{2 \cdot 147} : \frac{- 2 + 10}{3}

t = \frac{- 196 - 98 10}{2 \cdot 147} : - \frac{2 + 10}{3}

The solutions to the quadratic equation are:

t = \frac{- 2 + 10}{3}, t = - \frac{2 + 10}{3}

0.0001 (300)^{3} + 0.005 (300)^{2} + 28 (300) + 3000

x^{2} + 4 = 7 x - 3

(\frac{4}{7})^{- 1}

8 x^{2} - 43 x + 15

(\frac{12}{25} \cdot \frac{15}{7}) \div \frac{20}{7}

What are the solutions to the equation -4.9t^2=9.8t^2+19.6t-9.8 ?
The solutions to the equation -4.9t^2=9.8t^2+19.6t-9.8 are t=(-2+sqrt(10))/3 ,t=-(2+sqrt(10))/3
Find the zeros of -4.9t^2=9.8t^2+19.6t-9.8
The zeros of -4.9t^2=9.8t^2+19.6t-9.8 are t=(-2+sqrt(10))/3 ,t=-(2+sqrt(10))/3