What is (6y^5+4y^3-10y^2+2y)/(2y) ?

The solution to (6y^5+4y^3-10y^2+2y)/(2y) is 3y^4+2y^2-5y+1

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simplify (6y^5+4y^3-10y^2+2y)/(2y)

simplify

\frac{6 y ^{5} + 4 y ^{3} - 10 y ^{2} + 2 y}{2 y}

3 y^{4} + 2 y^{2} - 5 y + 1

Solution steps

\frac{6 y ^{5} + 4 y ^{3} - 10 y ^{2} + 2 y}{2 y}

Factor

6 y^{5} + 4 y^{3} - 10 y^{2} + 2 y : 2 y (3 y^{4} + 2 y^{2} - 5 y + 1)

= \frac{2 y ( 3 y ^{4} + 2 y ^{2} - 5 y + 1 )}{2 y}

Cancel the common factor:

2

= \frac{y ( 3 y ^{4} + 2 y ^{2} - 5 y + 1 )}{y}

Cancel the common factor:

y

= 3 y^{4} + 2 y^{2} - 5 y + 1

sin^{2} (q) + cos^{2} (q)

\frac{( 2 - x )}{( x - 2 )}

\frac{( 4 x ^{2} + 10 x )}{( 2 x )}

400 (m^{1})^{0} n^{4} - 280 m^{5} n^{2} y^{3} + 49 y^{6}

a - 5 + 6 - (- 6) + 7 - (- 8)

What is (6y^5+4y^3-10y^2+2y)/(2y) ?
The solution to (6y^5+4y^3-10y^2+2y)/(2y) is 3y^4+2y^2-5y+1