What is 400(m^1)^0n^4-280m^5n^2y^3+49y^6 ?

The solution to 400(m^1)^0n^4-280m^5n^2y^3+49y^6 is 400n^4-280m^5n^2y^3+49y^6

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simplify 400(m^1)^0n^4-280m^5n^2y^3+49y^6

simplify

400 (m^{1})^{0} n^{4} - 280 m^{5} n^{2} y^{3} + 49 y^{6}

400 n^{4} - 280 m^{5} n^{2} y^{3} + 49 y^{6}

Solution steps

400 (m^{1})^{0} n^{4} - 280 m^{5} n^{2} y^{3} + 49 y^{6}

Apply exponent rule:

a^{0} = 1,

assuming

a \neq = 0

(m^{1})^{0} = 1

= 400 \cdot 1 \cdot n^{4} - 280 m^{5} n^{2} y^{3} + 49 y^{6}

Multiply the numbers:

400 \cdot 1 = 400

= 400 n^{4} - 280 m^{5} n^{2} y^{3} + 49 y^{6}

a - 5 + 6 - (- 6) + 7 - (- 8)

(5 x + 2 y) (6 x - 2 y) (2 x - y) (2 x + y)

a^{4} b^{- 4} + a^{2} b^{- 2} + 1

f (x) \cdot x^{3} - 3 x^{2} + 3

(\frac{x + x ^{2}}{2})^{2}

What is 400(m^1)^0n^4-280m^5n^2y^3+49y^6 ?
The solution to 400(m^1)^0n^4-280m^5n^2y^3+49y^6 is 400n^4-280m^5n^2y^3+49y^6