What is a^4b^{-4}+a^2b^{-2}+1 ?

The solution to a^4b^{-4}+a^2b^{-2}+1 is (a^4)/(b^4)+(a^2)/(b^2)+1

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simplify a^4b^{-4}+a^2b^{-2}+1

simplify

a^{4} b^{- 4} + a^{2} b^{- 2} + 1

\frac{a ^{4}}{b ^{4}} + \frac{a ^{2}}{b ^{2}} + 1

Solution steps

a^{4} b^{- 4} + a^{2} b^{- 2} + 1

b^{- 4} = \frac{1}{b ^{4}}

b^{- 2} = \frac{1}{b ^{2}}

= a^{4} \frac{1}{b ^{4}} + a^{2} \frac{1}{b ^{2}} + 1

a^{4} \frac{1}{b ^{4}} = \frac{a ^{4}}{b ^{4}}

a^{2} \frac{1}{b ^{2}} = \frac{a ^{2}}{b ^{2}}

= \frac{a ^{4}}{b ^{4}} + \frac{a ^{2}}{b ^{2}} + 1

f (x) \cdot x^{3} - 3 x^{2} + 3

(\frac{x + x ^{2}}{2})^{2}

\frac{( z ^{2} - 9 )}{( z ^{2} - 6 z + 9 )}

(\frac{2}{3} \cdot x - \frac{1}{4} \cdot y)^{2}

2 x + 4 + 5 x + 7

What is a^4b^{-4}+a^2b^{-2}+1 ?
The solution to a^4b^{-4}+a^2b^{-2}+1 is (a^4)/(b^4)+(a^2)/(b^2)+1