What is ((x^3-2x^2+1))/((x-1)) ?

The solution to ((x^3-2x^2+1))/((x-1)) is x^2-x-1

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simplify ((x^3-2x^2+1))/((x-1))

simplify

\frac{( x ^{3} - 2 x ^{2} + 1 )}{( x - 1 )}

x^{2} - x - 1

Solution steps

\frac{x ^{3} - 2 x ^{2} + 1}{x - 1}

Factor

x^{3} - 2 x^{2} + 1 : (x - 1) (x^{2} - x - 1)

= \frac{( x - 1 ) ( x ^{2} - x - 1 )}{x - 1}

Cancel the common factor:

x - 1

= x^{2} - x - 1

6 x^{3} \cdot y^{2} + 9 x^{2} \cdot y^{3} - 3 x^{2} \cdot y^{2}

\frac{m}{n ( \frac{y}{2} + m + 6 )}

\frac{( n - 2 ) !}{( n - 3 ) !}

\frac{\frac{3}{x}}{\frac{1}{2}}

2^{\frac{1}{- n}}

What is ((x^3-2x^2+1))/((x-1)) ?
The solution to ((x^3-2x^2+1))/((x-1)) is x^2-x-1