What is (((2z^4))/((3z^7)))^{-3} ?

The solution to (((2z^4))/((3z^7)))^{-3} is (27z^9)/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (((2z^4))/((3z^7)))^{-3}

simplify

(\frac{( 2 z ^{4} )}{( 3 z ^{7} )})^{- 3}

\frac{27 z ^{9}}{8}

Solution steps

(\frac{2 z ^{4}}{3 z ^{7}})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{2 z ^{4}}{3 z ^{7}})^{- 3} = \frac{1}{( \frac{2 z ^{4}}{3 z ^{7}} ) ^{3}}

= \frac{1}{( \frac{2 z ^{4}}{3 z ^{7}} ) ^{3}}

Simplify

(\frac{2 z ^{4}}{3 z ^{7}})^{3} : \frac{8}{27 z ^{9}}

= \frac{1}{\frac{8}{27 z ^{9}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{27 z ^{9}}{8}

(3 m - 4 n + 2 p)^{2}

arctan (\frac{( 1 + x ^{2} - 1 )}{x})

\frac{( x ^{2} - y ^{2} )}{2 x - 2 y}

(\frac{1 - 1}{n})^{n}

\frac{x}{12 a + b + 2 x ^{12} a ^{11} + b}

What is (((2z^4))/((3z^7)))^{-3} ?
The solution to (((2z^4))/((3z^7)))^{-3} is (27z^9)/8