What is (x^2-7x+1)-(3x^2-7x+4) ?

The solution to (x^2-7x+1)-(3x^2-7x+4) is -2x^2-3

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simplify (x^2-7x+1)-(3x^2-7x+4)

simplify

(x^{2} - 7 x + 1) - (3 x^{2} - 7 x + 4)

- 2 x^{2} - 3

Solution steps

(x^{2} - 7 x + 1) - (3 x^{2} - 7 x + 4)

Apply rule:

(a) = a

(x^{2} - 7 x + 1) = x^{2} - 7 x + 1

= x^{2} - 7 x + 1 - (3 x^{2} - 7 x + 4)

Apply the distributive law:

- (a - b) = - a + b

- (3 x^{2} - 7 x + 4) = - 3 x^{2} + 7 x - 4

= x^{2} - 7 x + 1 - 3 x^{2} + 7 x - 4

Group like terms

= x^{2} - 3 x^{2} - 7 x + 7 x + 1 - 4

Add similar elements:

x^{2} - 3 x^{2} = - 2 x^{2}

= - 2 x^{2} - 7 x + 7 x + 1 - 4

Add similar elements:

- 7 x + 7 x = 0

= - 2 x^{2} + 1 - 4

Subtract the numbers:

1 - 4 = - 3

= - 2 x^{2} - 3

sin^{4} (x) - 1

25 x^{2} - 100 x \cdot y^{2} + 100 y^{4}

\frac{\frac{1}{10} v}{v}

x^{2} ln (y^{3})

\frac{( 4 b ^{2} \cdot 2 b ^{3} )}{( 8 b )}

What is (x^2-7x+1)-(3x^2-7x+4) ?
The solution to (x^2-7x+1)-(3x^2-7x+4) is -2x^2-3