What is (x+2)^2-5x(x+7)-(x+1)^3 ?

The solution to (x+2)^2-5x(x+7)-(x+1)^3 is -x^3-7x^2-34x+3

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simplify (x+2)^2-5x(x+7)-(x+1)^3

simplify

(x + 2)^{2} - 5 x (x + 7) - (x + 1)^{3}

- x^{3} - 7 x^{2} - 34 x + 3

Solution steps

(x + 2)^{2} - 5 x (x + 7) - (x + 1)^{3}

Expand

(x + 2)^{2} : x^{2} + 4 x + 4

= x^{2} + 4 x + 4 - 5 x (x + 7) - (x + 1)^{3}

Expand

- 5 x (x + 7) : - 5 x^{2} - 35 x

= x^{2} + 4 x + 4 - 5 x^{2} - 35 x - (x + 1)^{3}

Expand

- (x + 1)^{3} : - x^{3} - 3 x^{2} - 3 x - 1

= x^{2} + 4 x + 4 - 5 x^{2} - 35 x - x^{3} - 3 x^{2} - 3 x - 1

Group like terms

= - x^{3} + x^{2} - 5 x^{2} - 3 x^{2} + 4 x - 35 x - 3 x + 4 - 1

Add similar elements:

x^{2} - 5 x^{2} - 3 x^{2} = - 7 x^{2}

= - x^{3} - 7 x^{2} + 4 x - 35 x - 3 x + 4 - 1

Add similar elements:

4 x - 35 x - 3 x = - 34 x

= - x^{3} - 7 x^{2} - 34 x + 4 - 1

Subtract the numbers:

4 - 1 = 3

= - x^{3} - 7 x^{2} - 34 x + 3

\frac{( 35 b - 42 )}{( 14 b - 7 )}

\frac{x ^{2}}{( \frac{( 1 + x )}{( 1 - x )} )}

(i) \cdot x^{x^{2}}

(\frac{x - 1}{2 x ^{2} y})^{2}

\frac{( 1 + x + x ^{2} - 1 )}{x}

What is (x+2)^2-5x(x+7)-(x+1)^3 ?
The solution to (x+2)^2-5x(x+7)-(x+1)^3 is -x^3-7x^2-34x+3