What is 2x+1>=-7\land 2x+1<3 ?

The solution to 2x+1>=-7\land 2x+1<3 is -4<= x<1

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2x+1>=-7\land 2x+1<3

2 x + 1 \geq - 7 and 2 x + 1 < 3

- 4 \leq x < 1

Interval Notation

[- 4, 1)

Solution steps

2 x + 1 \geq - 7 and 2 x + 1 < 3

2 x + 1 \geq - 7 : x \geq - 4

2 x + 1 < 3 : x < 1

Combine the intervals

x \geq - 4 and x < 1

Merge Overlapping Intervals

- 4 \leq x < 1

3 t^{2} - 14 t + 5 = 0

5 = \frac{2}{3} (8 x - 6)

3 e^{- 3}

(x^{2})^{\frac{2}{5}}

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