What is factor n+2m^2+1+2m^2n ?

The solution to factor n+2m^2+1+2m^2n is (2m^2+1)(n+1)

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factor n+2m^2+1+2m^2n

factor

n + 2 m^{2} + 1 + 2 m^{2} n

(2 m^{2} + 1) (n + 1)

Solution steps

n + 2 m^{2} + 1 + 2 m^{2} n

Group by common factors

= 2 n m^{2} + n + 2 m^{2} + 1

= (2 n m^{2} + n) + (2 m^{2} + 1)

Factor out

n

from

2 n m^{2} + n : n (2 m^{2} + 1)

= n (2 m^{2} + 1) + (2 m^{2} + 1)

Factor out common term

(2 m^{2} + 1) : (2 m^{2} + 1) (n + 1)

= (2 m^{2} + 1) (n + 1)

\frac{( x ^{n + 1} + x ^{n - 1} )}{( x ^{2} + 1 )}

- (a + b) 3 - 8 (a - b)^{3}

7 a - 8 b - 9 a + 2 b

\frac{n !}{( 2 n ! )}

- 3 x - 3 y

What is factor n+2m^2+1+2m^2n ?
The solution to factor n+2m^2+1+2m^2n is (2m^2+1)(n+1)