What is (2^0+3^{-1})*(x^3)^2 ?

The solution to (2^0+3^{-1})*(x^3)^2 is 4/3 x^6

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simplify (2^0+3^{-1})*(x^3)^2

simplify

(2^{0} + 3^{- 1}) \cdot (x^{3})^{2}

\frac{4}{3} x^{6}

Solution steps

(2^{0} + 3^{- 1}) (x^{3})^{2}

Simplify

2^{0} + 3^{- 1} : \frac{4}{3}

= \frac{4}{3} (x^{3})^{2}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

(x^{3})^{2} = x^{3 \cdot 2}

= \frac{4}{3} x^{3 \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{4}{3} x^{6}

\frac{( x ^{3} + 4 x ^{2} - x - 4 )}{( x ^{2} + 3 x - 4 )}

5 a^{2} \cdot b^{2} \cdot c^{2}

5 - (3 x^{2} - 2 x) (6 - 3 x^{2} + 2 x)

- 2 x^{35} f^{5} - 316

a^{3} \cdot x - a^{2} \cdot y